In the solubility product expression for Sn(OH)2, the exponent on hydroxide is

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In the solubility product expression for Sn(OH)2, the exponent on hydroxide is

The solubility product exponent mirrors the number of hydroxide ions produced when the solid dissolves. Sn(OH)2(s) dissolves as Sn2+(aq) and 2 OH−(aq), so the Ksp expression uses the activities raised to those stoichiometric powers: Ksp ≈ [Sn2+][OH−]^2. The hydroxide exponent is 2 because two hydroxide ions are formed for each Sn(OH)2 unit that dissolves. Using concentrations is a good approximation in dilute solutions since activities ≈ concentrations.

The solubility product exponent mirrors the number of hydroxide ions produced when the solid dissolves. Sn(OH)2(s) dissolves as Sn2+(aq) and 2 OH−(aq), so the Ksp expression uses the activities raised to those stoichiometric powers: Ksp ≈ [Sn2+][OH−]^2. The hydroxide exponent is 2 because two hydroxide ions are formed for each Sn(OH)2 unit that dissolves. Using concentrations is a good approximation in dilute solutions since activities ≈ concentrations.

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